Optimal. Leaf size=113 \[ \frac {\left (a e^2+3 c d^2\right ) \tan ^{-1}\left (\frac {\sqrt {c} x}{\sqrt {a}}\right )}{8 a^{5/2} c^{3/2}}-\frac {2 a d e-x \left (a e^2+3 c d^2\right )}{8 a^2 c \left (a+c x^2\right )}-\frac {(d+e x) (a e-c d x)}{4 a c \left (a+c x^2\right )^2} \]
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Rubi [A] time = 0.05, antiderivative size = 113, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, integrand size = 17, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.176, Rules used = {739, 639, 205} \begin {gather*} \frac {\left (a e^2+3 c d^2\right ) \tan ^{-1}\left (\frac {\sqrt {c} x}{\sqrt {a}}\right )}{8 a^{5/2} c^{3/2}}-\frac {2 a d e-x \left (a e^2+3 c d^2\right )}{8 a^2 c \left (a+c x^2\right )}-\frac {(d+e x) (a e-c d x)}{4 a c \left (a+c x^2\right )^2} \end {gather*}
Antiderivative was successfully verified.
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Rule 205
Rule 639
Rule 739
Rubi steps
\begin {align*} \int \frac {(d+e x)^2}{\left (a+c x^2\right )^3} \, dx &=-\frac {(a e-c d x) (d+e x)}{4 a c \left (a+c x^2\right )^2}+\frac {\int \frac {3 c d^2+a e^2+2 c d e x}{\left (a+c x^2\right )^2} \, dx}{4 a c}\\ &=-\frac {(a e-c d x) (d+e x)}{4 a c \left (a+c x^2\right )^2}-\frac {2 a d e-\left (3 c d^2+a e^2\right ) x}{8 a^2 c \left (a+c x^2\right )}+\frac {\left (3 c d^2+a e^2\right ) \int \frac {1}{a+c x^2} \, dx}{8 a^2 c}\\ &=-\frac {(a e-c d x) (d+e x)}{4 a c \left (a+c x^2\right )^2}-\frac {2 a d e-\left (3 c d^2+a e^2\right ) x}{8 a^2 c \left (a+c x^2\right )}+\frac {\left (3 c d^2+a e^2\right ) \tan ^{-1}\left (\frac {\sqrt {c} x}{\sqrt {a}}\right )}{8 a^{5/2} c^{3/2}}\\ \end {align*}
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Mathematica [A] time = 0.07, size = 101, normalized size = 0.89 \begin {gather*} \frac {\left (a e^2+3 c d^2\right ) \tan ^{-1}\left (\frac {\sqrt {c} x}{\sqrt {a}}\right )}{8 a^{5/2} c^{3/2}}+\frac {-a^2 e (4 d+e x)+a c x \left (5 d^2+e^2 x^2\right )+3 c^2 d^2 x^3}{8 a^2 c \left (a+c x^2\right )^2} \end {gather*}
Antiderivative was successfully verified.
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IntegrateAlgebraic [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {(d+e x)^2}{\left (a+c x^2\right )^3} \, dx \end {gather*}
Verification is not applicable to the result.
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fricas [A] time = 0.41, size = 359, normalized size = 3.18 \begin {gather*} \left [-\frac {8 \, a^{3} c d e - 2 \, {\left (3 \, a c^{3} d^{2} + a^{2} c^{2} e^{2}\right )} x^{3} + {\left (3 \, a^{2} c d^{2} + a^{3} e^{2} + {\left (3 \, c^{3} d^{2} + a c^{2} e^{2}\right )} x^{4} + 2 \, {\left (3 \, a c^{2} d^{2} + a^{2} c e^{2}\right )} x^{2}\right )} \sqrt {-a c} \log \left (\frac {c x^{2} - 2 \, \sqrt {-a c} x - a}{c x^{2} + a}\right ) - 2 \, {\left (5 \, a^{2} c^{2} d^{2} - a^{3} c e^{2}\right )} x}{16 \, {\left (a^{3} c^{4} x^{4} + 2 \, a^{4} c^{3} x^{2} + a^{5} c^{2}\right )}}, -\frac {4 \, a^{3} c d e - {\left (3 \, a c^{3} d^{2} + a^{2} c^{2} e^{2}\right )} x^{3} - {\left (3 \, a^{2} c d^{2} + a^{3} e^{2} + {\left (3 \, c^{3} d^{2} + a c^{2} e^{2}\right )} x^{4} + 2 \, {\left (3 \, a c^{2} d^{2} + a^{2} c e^{2}\right )} x^{2}\right )} \sqrt {a c} \arctan \left (\frac {\sqrt {a c} x}{a}\right ) - {\left (5 \, a^{2} c^{2} d^{2} - a^{3} c e^{2}\right )} x}{8 \, {\left (a^{3} c^{4} x^{4} + 2 \, a^{4} c^{3} x^{2} + a^{5} c^{2}\right )}}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.17, size = 95, normalized size = 0.84 \begin {gather*} \frac {{\left (3 \, c d^{2} + a e^{2}\right )} \arctan \left (\frac {c x}{\sqrt {a c}}\right )}{8 \, \sqrt {a c} a^{2} c} + \frac {3 \, c^{2} d^{2} x^{3} + a c x^{3} e^{2} + 5 \, a c d^{2} x - a^{2} x e^{2} - 4 \, a^{2} d e}{8 \, {\left (c x^{2} + a\right )}^{2} a^{2} c} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.05, size = 108, normalized size = 0.96 \begin {gather*} \frac {e^{2} \arctan \left (\frac {c x}{\sqrt {a c}}\right )}{8 \sqrt {a c}\, a c}+\frac {3 d^{2} \arctan \left (\frac {c x}{\sqrt {a c}}\right )}{8 \sqrt {a c}\, a^{2}}+\frac {\frac {\left (a \,e^{2}+3 c \,d^{2}\right ) x^{3}}{8 a^{2}}-\frac {d e}{2 c}-\frac {\left (a \,e^{2}-5 c \,d^{2}\right ) x}{8 a c}}{\left (c \,x^{2}+a \right )^{2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 3.02, size = 113, normalized size = 1.00 \begin {gather*} -\frac {4 \, a^{2} d e - {\left (3 \, c^{2} d^{2} + a c e^{2}\right )} x^{3} - {\left (5 \, a c d^{2} - a^{2} e^{2}\right )} x}{8 \, {\left (a^{2} c^{3} x^{4} + 2 \, a^{3} c^{2} x^{2} + a^{4} c\right )}} + \frac {{\left (3 \, c d^{2} + a e^{2}\right )} \arctan \left (\frac {c x}{\sqrt {a c}}\right )}{8 \, \sqrt {a c} a^{2} c} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 0.35, size = 101, normalized size = 0.89 \begin {gather*} \frac {\mathrm {atan}\left (\frac {\sqrt {c}\,x}{\sqrt {a}}\right )\,\left (3\,c\,d^2+a\,e^2\right )}{8\,a^{5/2}\,c^{3/2}}-\frac {\frac {d\,e}{2\,c}-\frac {x^3\,\left (3\,c\,d^2+a\,e^2\right )}{8\,a^2}+\frac {x\,\left (a\,e^2-5\,c\,d^2\right )}{8\,a\,c}}{a^2+2\,a\,c\,x^2+c^2\,x^4} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 0.80, size = 172, normalized size = 1.52 \begin {gather*} - \frac {\sqrt {- \frac {1}{a^{5} c^{3}}} \left (a e^{2} + 3 c d^{2}\right ) \log {\left (- a^{3} c \sqrt {- \frac {1}{a^{5} c^{3}}} + x \right )}}{16} + \frac {\sqrt {- \frac {1}{a^{5} c^{3}}} \left (a e^{2} + 3 c d^{2}\right ) \log {\left (a^{3} c \sqrt {- \frac {1}{a^{5} c^{3}}} + x \right )}}{16} + \frac {- 4 a^{2} d e + x^{3} \left (a c e^{2} + 3 c^{2} d^{2}\right ) + x \left (- a^{2} e^{2} + 5 a c d^{2}\right )}{8 a^{4} c + 16 a^{3} c^{2} x^{2} + 8 a^{2} c^{3} x^{4}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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